Question

C) 10 W
b) 106 W
A water pump lifts water from a level 10 m below the ground. Water is pumped at a rate of 30 kg/minute
with negligible velocity. The minimum horse power the engine should have to do this is (
a) 6.6 x 10-2 hp
b) 66 x 104 hp
c) 0.66 x 10 hp
d) 6.6 x 10hp​

Answer 1

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Mass, pump Flow rate = 30 kg / min. =

30 kg / 60s. = 0.5 kg/s.

Height h = 10 m.

we know, pump water has negligible velocity, then its K.E is zero. Pump work to increase the level of water above 10 m.

Now weight of the water = mg

0.5 x 9.8 = 4.9 N.

Now power = mgh

P= 4.9 x 10 m

P= 49 W.

Now we know 1 hp = 746 W. =

So minimum power = 49 / 746

=0.066

= 6.6 x 10-2 hp.

Hence the minimum horsepower is 6.6*10-2 hp.

Answer 2

Step-by-step explanation:

option A is the right answer