Question

(c) 11ω – (30 w– 4) = 20
find the value of the variable involved​​

Answer 1

Step-by-step explanation:

X

L

=ωL=(2π×50)(35×10

−3

)=11Ω

∴ImpedanceZ=

R

2

+X

L

2

;Z=

(11)

2

+(11)

2

=11

2

Ω

∴I

0

=

Z

V

0

=

11

2

V

rms

×

2

=

11

220

=20A

Answer 2

11w-(3w-4)=20
11w-(3w-4)-(20)=0
11w-3w+4-20=0
8w-16=0
8w=16
w=8/16
w=2