Question

C
11. A block of iron has dimensions 2 m x 0.5 m
x 0.25 m. The density of iron is 7.8 g cm". Find
the mass of block.
Ans. 1950 kg
r​

Answer 1

Answer:

The mass of block = 1950 kg

Step-by-step explanation:

Given:

• Block of iron has dimensions 2 m x 0.5 m x 0.25 m.
• The density of iron is 7.8 g/cm³

To find:

• The mass of block.

Solution:

• Volume of block of iron = 2 × 0.5 × 0.25
• Volume of block of iron = 2 × 0.125
• Volume of block of iron = 0.25 m³
• Volume of block of iron = (0.25 × 100³ ) cm³
• Volume of block of iron = (25/100 × 100³ ) cm³
• Volume of block of iron = (25 × 100² ) cm³
• Volume of block of iron = 250000 cm³

We know that

Density = Mass per unit Volume

♦ Mass = Density × Volume

Putting the values in the formula, we have:

• Mass = 7.8 × 250000
• Mass = 78/10 × 250000
• Mass = 78 × 25000
• Mass = 1950000 g
• Mass = 1950000/1000 kg
• Mass = 1950 kg

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Answer 2

Answer:

${\large{\underline{\underline{\pmb{\sf{Given...}}}}}}$

• $\dashrightarrow$ A Block iron dimensions = 2 m x 0.5 m x 0.25 m.
• $\dashrightarrow$ The density of iron = 7.8 g cm³.

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{To \: Find...}}}}}}$

• $\dashrightarrow$ The mass of block

$\begin{gathered}\end{gathered}$

${\large{\pmb{\sf{\underline{\underline{Solution...}}}}}}$

$\bigstar{\underline{\underline{\frak{\green{Converting \: the \: block \: dimensions \: into \: cm}}}}}$

$: \implies{\bf{1 m = 100 cm}}$

$: \implies{\sf{2 m = 2 \times 100 cm}}$

$: \implies{\bf{\pink{200 \: cm}}}$

$: \implies{\sf{0.5 m = 0.5 \times 100 cm}}$

$: \implies{\bf{\pink{50 \: cm}}}$

$: \implies{\sf{0.25 m = 0.25 \times 100 cm}}$

$: \implies{\bf{\pink{25 \: cm}}}$

${\dag{\underline{\boxed{\sf{\red{Dimensions \: of \: iron \: block = 200 \: cm\times 50 \: cm \times 25 \: cm}}}}}}$

$\begin{gathered}\end{gathered}$

$\bigstar{\underline{\underline{\frak{\green{Finding \: the \: volume \: of \: block \: of \: iron}}}}}$

${: \implies{\sf{Volume \: of \: block \: of \: iron = 200 \times 50 \times 25}}}$

${: \implies{\bf{\pink{Volume \: of \: block \: of \: iron = 250000 \: {cm}^{3} }}}}$

$\dag{\underline{\boxed{\sf{\red{Volume \: of \: block \: of \: iron = 250000 \: {cm}^{3}}}}}}$

$\begin{gathered}\end{gathered}$

$\bigstar{\underline{\underline{\frak{\green{Now \: Finding \: the \: mass \: of \: iron \: block}}}}}$

${: \implies{\sf{Mass = Density \times Volume}}}$

• Substituting the values

${: \implies{\sf{Mass = 7.8\times 250000}}}$

${: \implies{\sf{Mass = \dfrac{78}{10} \times 250000}}}$

${: \implies{\sf{Mass = \dfrac{78}{\cancel{10}}\times \cancel{250000}}}}$

${: \implies{\sf{Mass = 78 \times 25000}}}$

${: \implies{\bf{\pink{Mass =1950000 \: g }}}}$

${: \implies{\sf{Mass = \dfrac{1950000}{1000}}}}$

${: \implies{\sf{Mass = \cancel{\dfrac{1950000}{1000}}}}}$

${: \implies{\bf{\pink{Mass = 1950 \: kg}}}}$

$\dag{\underline{\boxed{\sf{\red{Mass = 1950 \: kg}}}}}$

• Henceforth,The Mass of iron block is 1950 kg.

$\begin{gathered}\end{gathered}$

${\large{\underline{\underline{\pmb{\sf{Learn \: More...}}}}}}$

$\bigstar{\underline{\boxed{\sf{\purple{ Density= \dfrac{Mass}{Volume }}}}}}$

$\bigstar{\underline{\boxed{\sf{\purple{Mass = Density \times Volume}}}}}$

$\bigstar{\underline{\boxed{\sf{\purple{Volume = \frac{Mass}{Density}}}}}}$

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