Question

(c) 11
A body is projected at 30° angle with the horizontal
with velocity 30 m s-1. What is the angle with the
horizontal after 1.5 s? (Take g = 10 ms 4).​

Answer 1

Answer:

zero degree

Explanation:

Vy - final velocity at time "t" in y-direction

Vx - final velocity at time "t" in x-direction

Vx = Ux = 30 cos(30) = 15√3 m/s

Vy = Uy - gt = 30 sin(30) - 10 × 1.5

= 15 - 15 = 0

that means, body is at its highest point.

so, angle with horizontal = 0°

or,

tan(¢) = Vy / Vx = 0

=> ¢ = 0°