Math, asked by aswinr9, 5 hours ago

(c) 13 (d) 10 4. Kushal is a class X student residing in a village. Oneday, he went to a city Hospital along w grandfather for general check-up. From there he visited three places -School, Library and Police station returning to his village, he plotted a graph by taking Hospital as origin and marked three places on the gr per his direction of movement and distance. The graph is shown below. schoo -2 Labrar 1 վերանոր o X Polanlamind 1. What are the coordinates of library a) (6,2) b) (2,6) c) (2,-1) d) (2,3) 11. Distance between school and hospital Is(in units) a) 711 b) V13 c) vs d) v17 m. Distance between school and police station is(in units) a) 4 b) 3 c)2 d) 1 1 iv. Distance between police station and hospital Is(in units) a) 2 b) V5 c) d) 3.5 A1​

Answers

Answered by tabassumfouzia978
3

Answer:

Down Below

Step-by-step explanation:

Hmmmmmm I am not sure but the answer is between school and police is

(b) 3 and distance between police station and hospital is (c) 3.5

MARK ME BRAINLIEST

9

Answered by jhangir789
1

(1) Distance between school and hospital is:

$$\begin{aligned}\text { Distance } &=\sqrt{(2-0)^{2}+(3-0)^{2}} \\&=\sqrt{4+9}\\=\sqrt{13}\end{aligned}$$\

(2) Distance between school and police station :

Answer is, 4.

(3) Distance between police station and library :

$\begin{aligned} \text { Distance } &=\sqrt{(6-2)^{2}+(2+1)^{2}} \\ &=\sqrt{16+9}=\sqrt{25}=5 \end{aligned}$

(4) Nearest place to library is :

Let the take points S, L , P, H for School, Library, Police Station and Hospital respectively.

$$\text { Distance, } \begin{aligned}\mathrm{LS} &=\sqrt{(6-2)^{2}+(2-3)^{2}} \\&=\sqrt{16+1}=\sqrt{17}\end{aligned}$$Distance, $\mathrm{LP}=5$$$\text { Distance, } \begin{aligned}\mathrm{LH} &=\sqrt{(6-0)^{2}+(2-0)^{2}} \\&=\sqrt{16+4}=\sqrt{20}\end{aligned}$$

Answer is, School.

#SPJ2

Attachments:
Similar questions