Question

c) 180 J of heat is produced each second in a 512 resistance. Find the
potential difference across the resistor and current flowing through it.

Answer - E =180J
t=1 sec
R=5 ohm
E=l^2Rt
180=l^2 × 5×1
180=l^2×5
l^2=180÷5
l^2=36
l=6
or l = 6A
v=lR
v=6×5
v=30​

Answer 1

Answer:

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Answer 2

Explanation:

E =180J

t=1 sec

R=5 ohm

E=l^2Rt

180=l^2 × 5×1

180=l^2×5

l^2=180÷5

l^2=36

l=6

or l = 6A

v=lR

v=6×5

v=30