Question

(c) 2:1
(d) 4 : 1.
In the fig., ABCD is a A
square in which length
of diagonal is 46 cm.
Radius of each small
circle is one-fourth of
the radius of larger
circle, then length of
radius of each small
Da
circle is:
(a) (5-2) cm (b) (5+V2) cm
(C) 2(5-V2) cm (d) 2(15+V2) cm.​

Answer 1

Answer:

your answer is option (D)

Answer 2

Answer:

Let's r and R are the radius of Small and large circle respectively.

Hence r = 4 R , because r = R/4

Given

Diagonal AC=BD=46cm

Now from the figure,

r+r+R+R+r+r<46 cm

Or, r+r+4r+4r+r+r<46cm

Or, 12r<46cm

Now, checking for each option

a. When r= (5-√2)

Then, 12×(5-√2)<46cm

Or, 43.029<46cm

Hence, option (a) is correct.