C=(2,4,4,5) D=(a, b,c) solve it
Answers
Answer:
—— (1) : (2)
A:B = 2 : 3
B:C = 4 : 5
C:D = 6 : 7
A is the product of all terms appearing under column (1).
A = 2 x 4 x 6 = 48
B is the product of all terms under column (1) beginning from second row and term under column (2) for all previous rows.
B = 4 x 6 x 3 = 72
C is the product of all terms under column (1) beginning from third row and terms under column (2) for all previous rows.
C = 6 x 3 x 5 = 90
D is the product of all terms appearing under column (2).
D = 3 x 5 x 7 = 105
=> A:B:C:D = 48:72:90:105
You can find ratio between any two or three variables from above.
A:D = 48:105 = 16:35
Note : This logic can be extended to any number of rows
If A:B, B:C, C:D, D:E, E:F, F:G, G:H, H:I is given, we can find A:B:C:D:E:F:G:H:I using above method.
Example :
A:B = 1:2
B:C = 2:7
C:D = 3:5
D:E = 3:8
E:F = 1:3
F:G = 2:5
G:H = 3:2
H:I = 1:5
A = 1*2*3*3*1*2*3*1 = 108
B = 2*3*3*1*2*3*1*2 = 216
C = 3*3*1*2*3*1*2*7 = 756
D = 3*1*2*3*1*2*7*5 = 1260
E = 1*2*3*1*2*7*5*8 = 3360
F = 2*3*1*2*7*5*8*3 = 10080
G = 3*1*2*7*5*8*3*5 = 25200
H = 1*2*7*5*8*3*5*2 = 16800
I = 2*7*5*8*3*5*2*5 = 84000
A:B:C:D:E:F:G:H:I
=108:216:756:1260:3360:10080:25200:16800:84000
= 27:54:139:320:840:2520:6300:4200:21000
Explanation: