(c)2(a + b 2. Four coins are tossed. The chance of getting none of the face as head is
a) 1/16
b)1/8
c)1/6
d)3/4
Answers
Answered by
1
Answer:
Solution
Coin is tossed four times
So total number of outcomes =2
4
=16
Number of ways of getting two heads =
4
C
2
=
(4−2)!2!
4!
=
2!2!
4!
=6
Now number of ways of getting two tails =
2
C
2
=1
∴ required probability =
16
6
=
8
3
Step-by-step explanation:
Similar questions