Question

C С
2. In AABC, if ZA = 82°, ZB = 53º, find ZC.​

Answer 1

Answer:

‹A + ‹B + ‹C = 180° ( s. of all angles in a Δ)

‹c = 180° - 82° - 53° = 45°

therefore,,,,, ‹ C = 45°

Answer 2

Given,

in Triangle ABC

angle A=82°

angle B=53°

angle C=?

Let us take angle C=x

We know that,

Sum of all angles of a triangle=180°

angle A + angle B + angle C = 180°

82°+53°+x=180°

135°+x=180°

x=180°-135°

x=45°

Therefore Angle C=45°