Question

C 2. The n'" term of an arithmetic progression is a = 4n+ 5 then the 3rd term is : A. 5 B. 9 D. 17 C. 13​

Answer 1

Answer:

Given :-

→ \sf{n^{th}}nth term of the AP = 4n +5

To find :-

\sf{3^{rd}}3rd  term of the AP

Solution :-

Let \sf{t_{n}}tn denote the \sf{n^{th}}nth  term of the sequence

\sf{t_{n}= 4n + 5}tn=4n+5  

So, first term = \sf{t_{1}}t1 \sf{= 4(1)+5 = 9}=4(1)+5=9

Second term =  \sf{t_{2} = 4(2) + 5 = 13}t2=4(2)+5=13

Third term = \sf{t_{3} = 4(3) + 5 = 17 }t3=4(3)+5=17

               \boxed{\sf{t_{3} = 17 }}t3=17

\bold{3^{rd} \ term \ of \ the \ AP = 17}3rd term of the AP=17

Answer 2

Answer:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.