c) 27 col 3 [1 6. Ifn= 23 x 34 x 54 x 7, then the number of consecutive zeros in n, where n is a natural number, is
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In 23×34×54×7, number of consecutive zero will be 3 as 23×54 = 2 × 2 × 2×5 × 5 ×5 = 5000.
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