C=3+0.2y, I=13
Find Y
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c=13
13=3+0.2y
13-3=0.2y
10=0.2y
y=10/0.2
y=10/2/10
y=10/1/5
y=10×5
y=50
13=3+0.2y
13-3=0.2y
10=0.2y
y=10/0.2
y=10/2/10
y=10/1/5
y=10×5
y=50
soumya834:
when we send 0.2 to other side it will be divided
then I written 0.2= 2/10 =1/5
Yes but how it is become 50 could u please teach me
10/1/5 right now 1/5 is reciprocaled and becomes 5/1 so it is 10×5/1 =50
Can we write directly ..that is y = 10/0.2 is .e 50
Ya we can if u are perfect
I expanded for ur better understandable
One questions..10/2/10
How it become
10/2/10 = 10/1/5 =10×5/1 =50/1 =50
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