Question

(c) 3%
2%
11. The RBI lends a certain amount to the SBI on simple
interest for two years at 20%. The SBI gives this
entire amount to Bharti Telecom on compound inter-
est for two years at the same rate annually. Find the
percentage earning of the SBI at the end of two years
on the entire amount.
(a) 4%
(b) 3(1/7)%
(c) 3(2/7)%
(d) 3(6/7)%
12. Find the compound interest on 64,000 for 1 year
c10/

Answer 1

Answer:

The cytoplasm is a fluid that contains all the cell organelles such as the Mitochondria, Ribosomes, Golgi bodies, etc. It is present between the nucleus and the plasma membrane.

Step-by-step explanation:

Answer 2

Answer:

Let P is faster than Q

Then P covers 72 km distance in the same time as Q covers 48 km distance

Ratio of the speed = 72 : 48 = 3 : 2

∴Speed of faster train i.e., P = 48/2×3=72 km/hr

Quantity 1→ Difference between P and Q = 72 – 48 = 24 km/hr.

Let speed of train = T km/hr

Let speed of car = C km/hr

∴ 120/+480/=8 ………..(i)

200/+400/=8 1/3 ………(ii)

On solving (i) and (ii)

T = 60 km/hr

∴ Quantity I < Quantity II

S6. Ans.(d)

Sol.

Rate on SI for SBI = 15 × 2 = 30%

Rate on CI for Bharti telecom =15+15+ (15×15)/100

= 32.25

Percentage earning of SBI = 2.25%

S7. Ans.(a)

Sol.

Let, A can complete the work alone in ‘x’ days

B can complete the work alone in ‘y’ days 1/+1/=15 ..()

And,

2/+1/2=14 …()

On solving (i) & (ii)

x = 10 days, y =10 days

S8. Ans.(c)

Sol

Time when X and Y meet first time

=300/(25+15)=300/40=7.5 hr

Distance travelled by X = 7.5 × (25 + 5) = 225 km

Distance travelled by Y = 7.5 × (15 – 5) = 75 km

X reach at point Q in 75/30 i.e. 2.5 hour

In 2.5hr Y travelled 2.5 × 10 = 25 km

Now Boat X return and relative distance b/w X and Y is 100 km and relative speed is 10 km i.e. difference of speed of X (25 -5) = 20 km/hr (upstream) and speed of Q (15 – 5) = 10 km/hr (upstream)

Time taken by X and Y to meet =100/10=10 hr

Total time when X and Y meet second time = 7.5 +2.5 + 10 = 20 hr

S9. Ans.(a)

Sol.

2ℎ/2ℎ=616/352

=3.5 m

2ℎ=616

ℎ=616/(11×3.5)=16 m

Total S.A. =2ℎ+22

=2(ℎ+)

=2×22/7×3.5(3.5+16)

=429 m

S10. Ans.(c)

Sol. Amount

4000

rate

20%

At end of 1st year

4000 + 800 = 4800

Amount

4800 – 1500 = 3300

At the end of 2nd year

3300 + 660 = 3960

Amount

3960 – 1500 = 2460

Amount to be paid at the end of third year = 2460 + 492 = 2952