Math, asked by ishu727590, 10 months ago

(c) 3
(d) none of the
1. Out of 2000 employees in an office 48% preferred Coffee (c), 54% liked m
smoke (S). Out of the total 28% used C and T, 32% used T and S and 30% pre
e
only 6% did none of these. The number having all the three is
(a) 360
(b) 300
(c) 380
(d) none of the
. Referred to the data of Q. 21 the number of employees having T and S but not
(a) 200
(b) 280
(c) 300
(d) none of these
Referred to the data of Q. 21 the number of employees preferring only coffee is
(a) 100
(b) 260
(c) 160
(d) none of the​

Answers

Answered by charulsingh35
18

given

n(c) =48%

n(S) =64%

n(T) 54%

n(CnT) = 28%

n(TnS)= 32%

n(CnS)=30%

none = 6%

  • . n(CuTuS) = n(C)+n(T)+n(S) +n(CnTnS)-n(CnT)-n(TnS)-(CnS) + none

=100=48+54+64+x-28-32-30+6

=n(CnTnS) = 18%

ans 18% of 2000= 360 people

n(TuS) = n(TuS) -n(CnTnS)

= 32-18

=14% of 2000= 280

Answered by 918319898057
3

Answer:

Referred to the data of Q. 21 the number of employees having T and S but not

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