Question

(c) 4
19. The digit by which * should be replaced in 54 * 281 so that the number formed
divisible by 9 is
(a) 6
(b) 7
20. The digit by which **' should be replaced in 7254 * 98 so that the number formed
(c) 8
(d) 9
divisible by 22 is
(a) o
(b) 1
21. If a number is divisible by 5 and 6 both, then it may not be divisible by
(c) 2
(d) 6
(a) 10
(b) 15
22. The number of common prime factors of 60, 75 and 105 is
(c) 30
(d) 60
(a) 2
(b) 3
23. The HCF of 144 and 198 is
(d) 5
(a) 6
(6) 9
(c) 12
(d) 18
24. The LCM of 30 and 45 is
(a) 15
(b) 30
(C) 45
(d) 90
25. If HCF of two numbers is 15 and their product is 1575, then their LCM is
(a) 15
(b) 105
(c) 525
(d) 1575
26. If the LCM of two natural numbers is 180, then which of the following is not t
of the numbers?
(a) 45
(b) 60
(C) 75
(d) 90
clrill (HOTS)​

Answer 1

Answer:

Answer

Correct option is

B

7

For a number to be divisible by 9 , sum of its digits should be divisible by 9 .

Sum of given digits in 54∗281

=5+4+2+8+1=20

if we add 7 , it becomes 27 , which is divisible by 9.

∴∗ is to be replaced by 7.

Step-by-step explanation:

o

(b) 1

21. If a number is divisible by 5 and 6 both, then it may not be divisible by

(c) 2

(d) 6

(a) 10

(b) 15

22. The number of common prime factors of 60, 75 and 105 is

(c) 30

(d) 60

(a) 2

(b) 3

23. The HCF of 144 and 198 is

(d) 5

(a) 6

(6) 9

(c) 12

(d) 18

24. The LCM of 30 and 45 is

(a) 15

(b) 30

(C) 45

(d) 90

25. If HCF of two numbers is 15 and their product is 1575, then their LCM is

(a) 15

(b) 105

(c) 525

(d) 1575

26. If the LCM of two natural numbers is 180, then which of the following