Question

C-4. Insulin contains 3.4% sulphur by mass. What will be the minimum molecular weight of insulin - (A) 94.117 (B) 1884 (C) 941 (D) 976 C-5. The percent of N in 66% pure (NH4 )2 SO4 sample is - (A) 32 (B) 28 (C) 14 (D) None of these C-6. A compound was found to contain 5.37% nitrogen by mass. What is the minimum molecular weight of compound- (A) 26.07 (B) 2.607 (C) 260.7 (D) None C-7. Calculate the molecular formula of compound which contains 20% Ca and 80% Br (by wt.) if molecular weight of compound is 200. (Atomic wt. Ca = 40, Br = 80) (A) Ca1/2Br (B) CaBr2 (C) CaBr (D) Ca2Br C-8. The empirical formula of a compound is CH. Its molecular weight is 78. The molecular formula of the compound will be - (A) C2H2 (B) C3H3 (C) C4H4 (D) C6H6 C-9. An oxide of a metal (M) contains 40% by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is- (A) M2O (B) MO (C) M2O3 (D) M3O4 C-10. Two oxides of Metal contain 27.6% and 30% oxygen respectively. If the formula of first oxide is M3O4 then formula of second oxide is -

Answer 1

Answer:

Insulin contains 3.4% sulphur by mass. What will be minimum molecular weight of insulin?

A .

94.117

B .

1884

C .

941

D .

976

December 26, 2019Nishar Lalani

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ANSWER

Let us consider,

For, 3.4gm sulphur =100gm insulin

Now molecular mass of sulphur is 32

∴32gm sulphur =3.4100×32

=941.176

So, the correct option is A

December 26, 2019Toppr