Question

(c) 4 x 87 x (-25) please solve this​

Answer 1

Step-by-step explanation:

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4t\imath mes\times 87t\imath mes(-25)

4tmes×87tmes(−25)

1 Take out the constants.

(4\times 87\times -25)ttmmss\imath e\imath e

(4×87×−25)ttmmssee

2 Simplify 4\times 874×87 to 348348.

(348\times -25)ttmmss\imath e\imath e

(348×−25)ttmmssee

3 Simplify 348\times -25348×−25 to -8700−8700.

-8700ttmmss\imath e\imath e

−8700ttmmssee

4 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

-8700{t}^{2}{m}^{2}{s}^{2}{\imath }^{2}{e}^{2}

−8700t

2

m

2

s

2



2

e

2

5 Use Square Rule: {i}^{2}=-1i

2

=−1.

-8700{t}^{2}{m}^{2}{s}^{2}\times -1\times {e}^{2}

−8700t

2

m

2

s

2

×−1×e

2

6 Simplify 8700{t}^{2}{m}^{2}{s}^{2}\times -1\times {e}^{2}8700t

2

m

2

s

2

×−1×e

2

to -8700{t}^{2}{m}^{2}{s}^{2}{e}^{2}−8700t

2

m

2

s

2

e

2

.

-(-8700{t}^{2}{m}^{2}{s}^{2}{e}^{2})

−(−8700t

2

m

2

s

2

e

2

)

7 Regroup terms.

-(-8700{e}^{2}{t}^{2}{m}^{2}{s}^{2})

−(−8700e

2

t

2

m

2

s

2

)

8 Remove parentheses.

8700{e}^{2}{t}^{2}{m}^{2}{s}^{2}

8700e

2

t

2

m

2

s

2

Done