Question

(C) 40%
שלרע)
The minimum mass of mixture of A, and B, required to produce at least 1 kg of each product is :
[Given : At mass of 'A' = 10; At. mass of 'B' = 120]
54, + 2B4 — 2AB, + 4A,B​

Answer 1

Answer:

Answer

Molar masses of AB

2

andA

2

B are 250 g/mol and 140 g/mole respectively.

1 kg of AB

2

corresponds to 4 moles. It requires 10 mole A

2

and 4 mole B

4

respectively.

1 kg of A

2

B corresponds to 7.14 mole. It requires 8.9 mole A

2

and 3.57 mole B

4

respectively.

Thus 10 mole A

2

(200 g) and 4 mole B

4

(1920 g) will produce atleast 1 kg of each product.

The minimum mass of mixture required is 200g+1920g=2120g.