Question

C) 4s^2-4s +1
find the zeros​

Answer 1

Answer:

4s^2 - 4s +1

=> 4s^2 -2s-2s +1

=> 2s(2s - 1) -1( 2s +1)

=>( 2s - 1) (2s - 1)

=> 2s - 1 = 0

=> 2s = 1

=> s = 1/2

ans In another case also

=> s = 1/2

Answer 2

Answer:

1/2 ,1/2

Step-by-step explanation:

4s^2-4s+1

4s^2 -(2s+2s) +1

4s^2-2s-2s+1

2s(2s-1)-1(2s-1)

(2s-1)(2s-1)

2s-1=0

2s=1

s=1/2