Math, asked by mohdhubaib77, 6 hours ago

C=5/9(F−32)

The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?

I. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9
degree Celsius.

II. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.

II. A temperature increase of 5/9
degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.

A) I only
B) II only
C) III only
D) I and II only​

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Answers

Answered by mathdude500
4

\large\underline{\sf{Solution-}}

Given that

 \red{\rm :\longmapsto\:C = \dfrac{5}{9}(F - 32)}

Now, Let we take Condition I.

I. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 5/9

degree Celsius.

➢ Let assume initially when F = y, the corresponding value of C is

 \red{\rm :\longmapsto\:C = \dfrac{5}{9}(y - 32)}

➢ Let assume that F take the value y + 1 and L let corresponding value of C be x.

So,

 {\rm :\longmapsto\:x = \dfrac{5}{9}(y + 1 - 32)}

 {\rm :\longmapsto\:x = \dfrac{5}{9}(y - 32)} + \dfrac{5}{9}

 \rm :\longmapsto\:x = C + \dfrac{5}{9}

\bf\implies \:x \: increased \: by \: \dfrac{5}{9}   \: \degree C

So,

\bf\implies \:\boxed{ \bf{ \: I \: is \: true}}

Now, Let we take Condition II.

II. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.

➢ Let assume that C take the value x + 1 and Let assume that corresponding value of F be y.

So,

 \red{\rm :\longmapsto\:C = \dfrac{5}{9}(F - 32)}

 \red{\rm :\longmapsto\:\dfrac{9}{5} C = F - 32}

 \red{\rm :\longmapsto\:F = \dfrac{9}{5} C  + 32}

➢ Now, Let assume initially when C = x, then F is

 \red{\rm :\longmapsto\:F = \dfrac{9}{5} x  + 32}

Now, on substituting the values of C and F we get

{\rm :\longmapsto\:y = \dfrac{9}{5}(x + 1) + 32}

{\rm :\longmapsto\:y = \dfrac{9}{5}x+ 32 + \dfrac{9}{5} }

{\rm :\longmapsto\:y =F+ \dfrac{9}{5} }

{\rm :\longmapsto\:y =F+ 1.8 }

\bf\implies \:y \: increased \: by \: 1.8   \: \degree F

\bf\implies \:\boxed{ \bf{ \: II \: is \: true}}

Now, Let take Condition III.

III. A temperature increase of 5/9 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.

➢ Let assume that F take the value y + 5/9 and corresponding value of C be x.

So,

 {\rm :\longmapsto\:x = \dfrac{5}{9}\bigg(y + \dfrac{5}{9}  - 32\bigg)}

 {\rm :\longmapsto\:x = \dfrac{5}{9}\bigg(y   - 32\bigg)  +  \dfrac{25}{81} }

 {\rm :\longmapsto\:x = C  +  \dfrac{25}{81} }

\bf\implies \:x \: increased \: by \: \dfrac{25}{81}   \: \degree C

\bf\implies \:\boxed{ \bf{ \: III \: is \: false}}

  • Hence, Option (D) is correct

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