Question

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5
AD is an altitude of an isosceles triangle ABC such
that it bisects the base BC. Co-ordinates of A and D
are (3, 1) and (3,-2) respectively. If the area of the
triangle is 12 sq units, which of the following could
be the coordinate of point B?
A
(7,1)
C
D
E
(43)
(-1, 1)
(-1, -2)
(7,-2)​

Answer 1

Step-by-step explanation:

AD=√(3-3)^2+(-2-1)

AD=√0+9

AD=3

AREA∆ABC=1/2×AD×BC

12Unit=1/2×3×BC

12Unit×2÷3=BC

8Unit=BC

Coordinate of B

X=x'+x"/2

3×2=x'+x"

6=x'+x"

Y=y'+y"/2

-2×2=y'+y"

-4=y'+y"