(C) 50,9
6. a, b and c are positive real numbers. If a 2 b, then :
(A) ac bc
(B) ac s bc
(C) ac
ac =
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0
Answer:
Given : a,b,c are in A.P
a
2
,b
2
,c
2
are in H.P
⟹
a
2
1
,
b
2
1
,
c
2
1
are in A.P.
then 2b=a+c ______ (1)
and
b
2
2
=
c
2
1
+
a
2
1
i.e
b
2
1
−
a
2
1
=
c
2
1
−
b
2
1
⇒
a
2
b
2
a
2
−b
2
=
c
2
b
2
b
2
−c
2
⇒
a
2
b
2
(a+b)(a−b)
=
c
2
b
2
(b−c)(b+c)
____ (1)
Now ∵a,b,c are in A.P
∴b−a=c−a
∴(1) becomes
a
2
a+b
=
c
2
b+c
⇒ac
2
+bc
2
=a
2
b+a
2
c
⇒bc
2
−a
2
b=0
⇒ac
2
−a
2
c=a
2
b−bc
2
⇒ac(c−a)+b(c−a)(c+a)=0
⇒(c−a)[ac+bc+ca]=0
⇒c=a or ab+bc+ca=0
⇒a=b=c then
b
a
+
c
b
+
a
c
=3
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