c) 50 J of work is done in moving 3 C of charge from one terminal of a battery to
another terminal. Calculate the potential difference of this battery.
Answers
Answer:
Solution :
⏭ Given:
✏ Work done to moving a charge = 50J
✏ Magnitude of charge = 3C
⏭ To Find:
✏ Potential difference across the battery.
⏭ Formula:
✏ Formula of work done in terms of charge and potential difference is given by
\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{W = q \triangle{V}}}}}}} \: \star⋆
W=q△V
⋆
⏭ Terms indication:
✏ W denotes work done
✏ q denotes charge
✏ ΔV denotes potential difference
⏭ Calculation:
\begin{gathered}\implies \sf \: \red{ \triangle{V} = \dfrac{W}{q}} \\ \\ \implies \sf \: \triangle{V} = \dfrac{50}{3} \\ \\ \implies \: \underline{ \boxed{ \bold{ \sf{ \orange{ \large{ \triangle{V} = 16.67 \: Volt}}}}}} \: \gray{ \bigstar}\end{gathered}
⟹△V=
q
W
⟹△V=
3
50
⟹
△V=16.67Volt
★
⏭ Additional information:
Electric potential is a scalar quantity while potential gradient is a vector quantity.
The electric potential due to a charge q at its own location is not defined-it is infinite.
Explanation:
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Answer:
as the formula is W=q∆v
50=3∆v
∆v=50/3
∆v=16.67
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