Question

c)
6 cm
2 cm
6 cm
4 cm
2 cm
4 cm
6 cm
6 cm​

Answer 1

What is this
I don’t understand

Answer 2

Give OC =4 cm, Chord AB =6 cm  

∵OC⊥AB⇒bisectsAB

⇒AC=CB=3cm

∴InOCA,OA  

2

+AC  

2

(PythagorasTheorem)

=4  

2

+3  

2

=16+9=25

⇒OA=5cm

Let EF be the chord at a distance of 3cm from the centre.

GIven, radius=OE =5 cm  

∴In△OGE,EG  

2

=OE  

2

−OG  

2

=5  

2

−3  

2

=25−9=16

⇒EG=4cm

∴EF=2×EG=8cm