Question

C-8.
Find the current through the 10 ohm resistor shown in figure
(A) zero
(B) 1 A
(C) 2A
(D) 5 A​

Answer 1

Answer:

Option ( A ) is correct.

Current through 10 ohm resistor is 0.

Explanation:

Refer the attached picture.

Answer 2

Answer:

The current through the 10 ohm is zero.

A is correct option.

Explanation:

Kirchhoff's law :

Kirchhoff's second law is defined the sum of a potential difference is equal to zero in any branch.

According to Kirchhoff's law

Kirchhoff's law in first loop

$10I_{1}+6(I_{1}+I_{2})-3=0$....(I)

Kirchhoff's law in second loop

$3I_{2}+6(I_{1}+I_{2})-4.5=0$....(II)

From equation (I) and (II)

$16I_{1}+6I_{2}=3$

$6I_{1}+9I_{2}=4.5$

On reducing of I₂

$96I_{1}=18$

$24I_{1}=18$

So, $I_{1}=0$

Hence, The current through the 10 ohm is zero.