(c+a)^3÷(b+d)^3=b(a-c)^4÷a(b-d)^4
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Given a:b=2:3,b:c=4:5,c:d=6:7
a:b=2×8:3×8=16:24
b:c=4×6:5×6=24:30
c:d=6×5:7×5=30:35
soa:b:c:d=16:24:30:35
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