(c++%++a) - (++b*c) solve in java programming.
Do only if you know.....java
AdeleDavis:
Ya sorry,
A = 2 B= 7and C=4
Answers
Answered by
0
(4%3)-(8*5)
=1-40
=-39
=1-40
=-39
Thnx
Could you pls solve this for same values....
(++a/b++) * --c *b
(++a/b++)* --c *b will yield 9/56
Answered by
1
Initial values:
a= 2
b=7
c=4
(c++%++a) - (++b*c)
Step 1: solving the first part
(c++%++a)
= 4 % (2+1) // c changes to 5 now
= 4%3
=1
New values:
a= 3
b=7
c=5
Second part :
(++b*c)
= (7+1)*5 // b changes to 8
= 8*5
=40
Now we have, 1-40
That gives : -39
Hope this helps!
-Sly
a= 2
b=7
c=4
(c++%++a) - (++b*c)
Step 1: solving the first part
(c++%++a)
= 4 % (2+1) // c changes to 5 now
= 4%3
=1
New values:
a= 3
b=7
c=5
Second part :
(++b*c)
= (7+1)*5 // b changes to 8
= 8*5
=40
Now we have, 1-40
That gives : -39
Hope this helps!
-Sly
Thnx a lot
You're welcome
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