c) A battery has an internal resistance of 0.2 Ω and a current of 4.5A flows through the battery. What is the potential difference lost across the internal resistance of the battery
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Potential across internal resistance = I × r = 4.5 ×2= 9V.
This much potential is lost.
Also power lost = I^2 r = 40.5W
This much potential is lost.
Also power lost = I^2 r = 40.5W
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