(c) A battery of 10 volt carries 20,000 C of charge
through a resistor. What is the work done?
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Answer:
2,00,000J or 2 x 10^5J
Explanation:
Voltage = 10V (10 volts)
q (charge) = 20,000C
Since Work done = Voltage x charge,
work done by the given battery = 10 x 20000 = 2,00,000J or 2 x 10^5J
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