Question

c)A body moving at 20 m/s, starts retarding uniformly at 2 m/s. Calculate the distance covered by it before
coming to rest .​

Answer 1

Answer:

$\boxed{\text{Answer: Distance travelled by the body = 300 metres}}$

Step-by-step explanation:

$\text{According to Kinematic equations:}\\\\\boxed{t = \frac{V_f - V_i}{a}}\\\\\text{In this case, } V_f \text{ = 0 m/s and } V_i \text{ = 20 m/s and a = 2 m/s}\\\\t = \frac{20}{2}\\\\t = \text{10 seconds}\\\\\boxed{\text{D = } V_i \text{ x } t + \frac{1}{2} \text{a} t^2}\\\\\\D = 20 \text{ x } 10 + \frac{2 \text{ x } 10^2}{2}\\\\D = 200 + 100\\\\\boxed{\text{Answer: } D = 300 \text{ metres}}$

Hope this helps!

Answer 2

this the answer of your question