Question

(c) A body of mass 200 g is moving with a speed of 50 m/s. It is brought to rest in 0.5 5.
Find: i) the change in momentum of the body.
ii) the force applied on it.
m) What can you conclude about the force?​

Answer 1

Answer:

mass of the ball (m) =100g or 0.1kg

initial velocity (u) =25

s

m

time (t) = 0.025sec.

final velocity (v) = 0

Initial momentum = mu

= 0.1×25

= 2.5

s

kgm

Final momentum = mv (which is equal to 0, since v is zero)

Change in momentum = mv-mu

= 0 - 2.5 = -2.5

s

kgm

Average force =

time

Changeinmomentum

= -

0.025

(2.5)

= -100 = -100 N

The negative sign actually shows that the force was applied

opposite to the direction of the motion of the ball.

So, the average force applied by the player will be 100