c) A bullet having a mass of 10 g and g moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity. (Ans: 0.15 m/s)
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mass of bullet=10g=0.01kg
velocity of bullet=1.5
s
m
mass of plank=90g=0.09kg
Total momentum before collision=mass of plank × velocity
=0.01×1.5+0.09×0=0.015kg
s
m
Total momentum after collision=(mass of bullet +mass of plank )× velocity
=0.1kg×V=0.1Vkg
s
m
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg
s
m
=0.1vkg
s
m
velocity acquired by the plank and the bullet=0.15
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