Question

[C] A bullet of mass 100 g moving with an initial velocity 100 ms-1
, strikes a wooden block and comes to
rest after penetrating a distance of 2 cm in it. Calculate:
[4]
(i) Initial momentum of the bullet, (ii) Final momentum of the bullet, and
(iii) Resistive force exerted by the wooden block.

Answer 1

Answer:

Explanation:

Given,

Mass,m=0.05kg Initial ve locity, v=100m/s,s=0.2m$$

i) Initial momentum =mu=0.05×100=5Ns

ii) Let a be the acceleration, then

v

2

=u

2

+2as⇒0=100

2

+2a×0.02⇒a=−2.5×10

5

m/s

2

So retardation acceleration is 2.5×10

5

m/s

2

iv) F=ma=0.05×−2.5×10

5

=12500N