(C)A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a
pistol of mass 2 kg. What is the recoil velocity of the pistol? (3)
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Answer:
Since bullet and pistol are at rest .., Total momentum before firing will be 0 ..
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Given :-
- A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg.
To Find :-
- The recoil velocity of the pistol.
Solution :-
A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg.
- Mass of bullet = 20 g = 0.02 kg
- Mass of pistol = 2 kg
- Velocity of bullet = 150 m/s.
Total mass = M(b) + M(p) = (0.02 + 2) kg = 2.02 kg
- Intial velocity is 0.
Hence, Initial momentum = 2.02 × 0 = 0
Final momentum = m1v1 + m2v2
= 0.02 × 150 + 2 × v2 ...(ii)
We know, Initial momentum = Final momemtum
➝ 0 = 0.02 × 150 + 2 × v2
➝0 = × 150 + 2 × v2
➝ 0 = 3 + 2v2
➝ -3 = 2v2
➝ v2 = 0.5m/s
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