Question

(C)A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a
pistol of mass 2 kg. What is the recoil velocity of the pistol? (3)​

Answer 1

Answer:

Since bullet and pistol are at rest .., Total momentum before firing will be 0 ..

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ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs◉‿◉

Answer 2

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Given :-

• A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg.

To Find :-

• The recoil velocity of the pistol.

Solution :-

A bullet of mass 20 g is horizontally fired with a velocity 150 m/s from a pistol of mass 2 kg.

• Mass of bullet = 20 g = 0.02 kg

• Mass of pistol = 2 kg

• Velocity of bullet = 150 m/s.

Total mass = M(b) + M(p) = (0.02 + 2) kg = 2.02 kg

• Intial velocity is 0.

Hence, Initial momentum = 2.02 × 0 = 0

Final momentum = m1v1 + m2v2

= 0.02 × 150 + 2 × v2 ...(ii)

We know, Initial momentum = Final momemtum

➝ 0 = 0.02 × 150 + 2 × v2

➝0 = $\dfrac{2}{100}$ × 150 + 2 × v2

➝ 0 = 3 + 2v2

➝ -3 = 2v2

➝ v2 = 0.5m/s

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