Math, asked by sanandwar, 4 months ago

c. A can complete a piece of work in 15 days and B can do the same
in 10 days. They worked together for 2 days and then Bleft. In
how many days will A complete the remaining work?​

Answers

Answered by anvisha27008
0

Answer:

A & B work together for 2 days.

It would take 8 more days had they continued to work together.

But, B only continues working for 12 more days. Splitting 12= 8 + 4, it is clear that B completes in 4 days that portion of work which A completes in 8 days.

=> Efficiency of A:B = 1:2

=> Time taken A:B = 2:1

Now 2x^2/3x = 10

=> x = 15

=> A alone can complete work in 2x or 30 days.

Step-by-step explanation:

A works for 2 days while B works for 2 + 12 days

In two days A & B together complete 2/10 = 20% work.

Remaining 80% work done by B in 12 days.

=> B alone completes full work in 12/80 x 100 = 15 days.

:-)

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