(c) A can do a piece of work in 20 days and B in 15
days. They worked together on it for 6 days and
then A left How long will B take to finish the
remaining work?
Answers
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Step-by-step explanation:
Given A can do the work in 20 days and B can do it 15 days.
Then work done by A in one day =
20
1
And, work by B in one day =
15
1
Then, the work done by A & B in one day =
20
1
+
15
1
=
60
7
A & B done 6 days together then work done in A & B in 6 days =
60
7
×6=
10
7
Then friction of work left =1−
10
7
=
10
3
Then B can do
10
3
work =
10
3
×
1
15
=
2
9
=4
2
1 days
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