Question

C). A constant force acts on an object of mass 10 kg for a duration of 2
seconds. It increases the object's velocity from 4m/s to 8 m/s. Find the magnitude of
the applied force. ​

Answer 1

Magnitude of the applied force = 20

Explanation:

Given,

Mass of the object (m) = 10 kg

Time (t) = 2 s

Initial velocity (u) = 4 m/s

Final velocity (v) = 8 m/s

Force (F) = ?

Using F = ma, we get

F = 10 × (v-u/t) (°•° a = v-u/t)

F = 10 × (8-4/2)

F = 10 × (4/2)

F = 10 × 2

•°• F = 20 N

Hence, the magnitude of the applied force is 20.

I hope this helps you. Adiós!