C). A constant force acts on an object of mass 10 kg for a duration of 2
seconds. It increases the object's velocity from 4m/s to 8 m/s. Find the magnitude of
the applied force.
Answers
Answered by
1
Answer:
F=ma
Explanation:
F=ma
=m(vf-vi)÷t
= 10kg×4m/s÷2
=10×2kgm/s²
=20kgms²
F = 20N
Similar questions