Question

(c)
A constant horizontal force 250 N acts for a distance of 36 m on a
500 kg box. If friction is neglected and the box starts from the rest,
what is its velocity?​

Answer 1

Answer:

Given :-

V = ? , U = 0 , F = 250N , M = 500 kg , a = ?

firstly we will find acceleration

a = F / m = 250 / 500 = 1/2 m/s2

Now V^2 = U^2 + 2as

V = √2×1/2×36

V = 6 m/sec