Question

c) A diver inside the sea experiences a pressure of 512500 pa. If the density of sea water is 1025kg/m?, at what depth is the diver inside the sea ? (Take g = 10m/s2)​

Answer 1

Answer:

50 Mtrs

Explanation:

1. pressure = density× acceleration due to gravity (g) × Height (h)
2. density × g = 1025×10= 10250.
3. height = pressure ÷ density×g.
4. 512500÷10250= 50 mtrs