Physics, asked by shampasharmin786, 3 months ago

(c) A helium-filled weather balloon is held at ground level. The volume of the balloon is 4800 m.
The pressure of the helium is 98 kPa.
The balloon is released and rises to a height where the volume of the balloon is 7200 mº.

Calculate the new pressure of the helium. Assume that the temperature stays constant
pressures

(11) Suggest why it may be necessary to release helium from the balloon as it rises even
higher

Answers

Answered by pt7882397
1

Answer:

  • 4/9^#8^/8673&/^/^67#94
Answered by pradeepchaklan9719
1

Answer:

P2 = 7200P2=7200

V1 = 4800V1=4800

V2 =?V2=?

Now,

P1 V1 = P2 V2 P1 V1=P2 V2

98,000 × 4800 = 7200 × V298,000×4800=7200×V2

V2 = \frac{98000 \times 4800}{7200}V2=

7200

98000×4800

V2 = 65,333.3V2=65,333.3

Therefore,

Pressure = 65,333.3

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