Question

c
A lift whose cage is 3 m high is moving up with an acceleration of 2 m/s. A piece of stone
is dropped from the top of the cage of the lift when its velocity is 8 mls. If g = 10 m/s?, then
the stone will reach the floor of the lift after
(A) 0.7 s
(B) 0.5 s
(C) 0.4 s
(D) 0.3 s.
Can anyone please answer this with proper explaination..? also mention the formulas used if possible n I'll mark you the brainliest.​

Answer 1

Answer:

0.3 s

Explanation:

The time taken to reach the stone on the floor is given as,

s=ut+21(a+g)t2

3=8×t+21(2+10)t2

3=8×t+6t2

t=0.3052sec

Answer 2

Answer:

the answer is 0.7 s

Explanation:

i hope it help us