Question

c)
A smooth circular cylinder of radius
1.5 meter is laying in a triangular groove as
shown. Find the reactions at the surface of
contact, if there is no friction and cylinder
weighs 100 N as shown.
C​

Answer 1

Answer:

PRINCIPLES OF EQUILIBRIUM 1. Two force principle. As per this principle, if a body in equilibrium is acted upon by two forces, then they must be equal, opposite and collinear. 2. Three force principle. As per this principle, if a body in equilibrium is acted upon by three forces, then the resultant of any two forces must be equal, opposite and collinear with the third force. 3. Four force principle. As per this principle, if a body in equilibrium is acted upon by four forces, then the resultant of any two forces must be equal, opposite and collinear with the resultant of the other two forces.

Answer 2

Explanation:

Given A smooth circular cylinder of radius  1.5 meter is lying in a triangular groove as  shown which makes 15 degree angle and the other 40 degree angle with the horizontal. Find the reactions at the surface of  contact, if there is no friction and cylinder  weighs 100 N

• The three forces R a, R b and weight must go through the centre of the cylinder.There will be no friction.
• So now by applying Lami’s theorem at point O we have,
• T / sin (180 – theta) = T / sin(180 – theta) = mg / sin 2 theta
• T / sin (180 – 40) = T / sin(180 – 15) = 100 / sin 55
• T / sin 140 = T / sin 165 = 100 / sin 55
•  R a / sin 140 = R b / sin 165 = 100 / 0.819
• Ra / 0.642 = R b / 0.258 = 100 / 0.819
• R a = 0.642 x 100 / 0.819
•   R a = 78.38 N
• R b = 100 x 0.258 / 0.819
• R b = 31.50 N

Reference link will be

https://brainly.in/question/15796793