Question

(C) A submarine is in water of density 1.0 103 kg/m3. The
submarine changes its depth. This causes the pressure on it to
change by 0.10 10 Pa. What is the change in depth of the
submarine? Take g = 10 m/s2. [2]​

Answer 1

Answer:

Depending on if your given pressure value is correct

1.01 ×10^-5 m

Explanation:

change_in_pressure = water_density * g * change_in_depth

change_in_depth = change_in_pressure / ( g * water_density)

water_density = 1000 kg/m³

g = 10 m/s²

change_in_pressure = 0.101 Pa ( ? I think. Question not quite clear)

change_in_depth = 0.101 [kg·m/s²] / (1000 [kg/m³] * 10 [m/s²]) = 1.01 ×10^-5 m