(C) A submarine is in water of density 1.0 103 kg/m3. The
submarine changes its depth. This causes the pressure on it to
change by 0.10 10 Pa. What is the change in depth of the
submarine? Take g = 10 m/s2. [2]
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Answer:
Depending on if your given pressure value is correct
1.01 ×10^-5 m
Explanation:
change_in_pressure = water_density * g * change_in_depth
change_in_depth = change_in_pressure / ( g * water_density)
water_density = 1000 kg/m³
g = 10 m/s²
change_in_pressure = 0.101 Pa ( ? I think. Question not quite clear)
change_in_depth = 0.101 [kg·m/s²] / (1000 [kg/m³] * 10 [m/s²]) = 1.01 ×10^-5 m
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