Physics, asked by anchalmishra1234444, 7 months ago

(c)
An electric motor of power 100 W is used to derive the stirrer in a water bath. If 50 % of the
energy supplied to the motor is spent in stirring the water, calculate the work done on water
in one minute.
[4]​

Answers

Answered by CopyThat
7

Answer:

  • 3000 J

Explanation:

Given

  • Power = 100 W
  • Time = 1 minute = 60 seconds
  • 50 % of the energy supplied to the motor spent in stirring the water.

To find

  • Work done one water in one minute.

Solution

Power used in stirring the water :

  • 50 % of power supplied
  • 50/100 × 100 W
  • 5/10 × 100
  • 50 W

Hence, the power used in stirring the water is 50 W.

Work done on water :

  • power × time
  • 50 W × 60 s
  • 3000 W.s
  • 3000 J

Hence, the work done on water is 3000 J.

Answered by peehuthakur
0

Answer:

Power supplied=100W, time t=60s

So, power used in stirring water = 50% of the power supplied=

100

50

×100W=50W

Work done on water = power used × time =50W×60s=3000J

Explanation:

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