(c) An object 4 cm high is placed at a distance of 6 cm in
concave mirror of focal length 12 cm. Find the position of the
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Solution :-
ho = + 4 cm
u = - 6 cm
f = - 12 cm
As we know that
→ 1/v + 1/u = 1/f
→ 1/v + 1/-6 = 1/-12
→ 1/v - 1/6 = - 1/12
→ 1/v = 1/6 - 1/12
→ 1/v = 2 - 1/12
→ 1/v = 1/12
→ v = + 12 cm
now,
→ hi/ho = - v/u
→ hi/4 = - 12/- 6
→ hi = + 8cm
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