Question

c) An object of mass 15 kg accelerates uniformly for 5 s such that its velocity changes from 36km/h to 72km/h
Find i) the change in momentum of the object and ii) the force acting on it.​

Answer 1

Answer:

22.5kg m/s^2

Explanation:

Answer 2

Answer:

(i) The change in momentum of the object is 540kg m/s.

(ii) The force acting on it is 108 N.

Explanation:

Firstly, Find the acceleration of an object = ?

Acceleration (a) = v-u/t

⟹ a = 72-36/5

⟹ a = 36/5

⟹ a = 7.2 m/s²

(i) The change in momentum of the object (∆P) = ?

⟹ Momentum (∆P) = m.(∆v)

⟹ ∆P = m(Vf - Vi)

⟹ 15 (72 - 36)

⟹ 15 × 36

⟹ 540kg m/s

∴ The change in momentum of the object is 540kg m/s.

(ii) The force acting on it = ?

⟹ Force (f) = mass × acceleration

⟹ F = ma

⟹ F = 15 × 70.2

⟹ F = 108 N

∴ The force acting on it is 108 N.