C and D are two observation posts on the same horizontal ground at the foot A of a vertical tower AB.The is 18m due north of D and 24m east of C. The angle of elevation of from D Is 35°. Calculate the height AB
distance CD
angle of elevation of B from
bearing of C from D
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As with all geometry problems, draw a diagram (plan).
You will find that in right triangle ABD, we know
AD=18 m
∠ADB=35°
Solve this triangle to get
mAB=AD tan(ADB)
=18tan(35°)
For right triangle CAB,
mAB (known from above)
mCA = 24m
=>
∠ACB=tan-1(mAB/mCA)
=angle of elevation of B relative to C.
Distance CD can be found by Pythagoras theorem
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