Question

C and d can finish a piece of work in 16 days and 12 days and 12 days respectively they started the work and worked at it for two days he was then joined by ID find the total time taken to finish the work

Answer 1

C's 1 day work = 1/16

D's 1 day work = 1/12

(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)

A's 2 day work = 2x(1/16) =1/8

Remaining work = 1–1/8 =7/8

( Total work is always presumed to be 1 in all such cases )

Now this remaining work will be done by A and B together .

(A+B)'s 1 day work = (1/16) + (1/12) = 7/48

A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days

Total time taken = 6+2 = 8 days